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fix variable name
1 parent 796f104 commit 727d068

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src/JsonApiDotNetCore.OpenApi/JsonApiSchemaIdSelector.cs

Lines changed: 6 additions & 6 deletions
Original file line numberDiff line numberDiff line change
@@ -77,18 +77,18 @@ public string GetSchemaId(Type type)
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return _formatter.FormatResourceName(type).Singularize();
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}
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80-
public string GetSchemaId(Type resourceObjectOpenType, ResourceObjectFieldType fieldType)
80+
public string GetSchemaId(Type resourceObjectType, ResourceObjectFieldType fieldType)
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{
82-
ArgumentGuard.NotNull(resourceObjectOpenType, nameof(resourceObjectOpenType));
82+
ArgumentGuard.NotNull(resourceObjectType, nameof(resourceObjectType));
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84-
if (!resourceObjectOpenType.IsConstructedGenericType || !_resourceObjectOpenTypes.Contains(resourceObjectOpenType.GetGenericTypeDefinition()))
84+
if (!resourceObjectType.IsConstructedGenericType || !_resourceObjectOpenTypes.Contains(resourceObjectType.GetGenericTypeDefinition()))
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{
86-
throw new InvalidOperationException($"Type '{resourceObjectOpenType.Name}' must be an open type representing a resource object.");
86+
throw new InvalidOperationException($"Type '{resourceObjectType.Name}' must be a resource object.");
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}
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89-
Type resourceClrType = resourceObjectOpenType.GetGenericArguments().First();
89+
Type resourceClrType = resourceObjectType.GetGenericArguments().First();
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string resourceName = _formatter.FormatResourceName(resourceClrType).Singularize();
91-
string template = OpenTypeToSchemaTemplateMap[resourceObjectOpenType.GetGenericTypeDefinition()];
91+
string template = OpenTypeToSchemaTemplateMap[resourceObjectType.GetGenericTypeDefinition()];
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string fieldObjectName = fieldType == ResourceObjectFieldType.Attributes
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? JsonApiObjectPropertyName.AttributesObject

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