doc : input voltage arduino nano

[lepirlouit]

page : https://store.arduino.cc/arduino-nano

In the "Tech" tab we can read that the input voltage is 7-12 Volt,
In the FAQ tab The Arduino Nano can be powered [...], 6-20V unregulated external power supply (pin 30),[...]

So, why is this not aligned ?

[ACanadianMoose]

I'm taking a guess here, but i think 6-20V is the "technically correct answer", while 7-12 V is the conservative answer.
Looking at the datasheet of the voltage regulator. You can see that maximum voltage is 20V (absolute maximum rating, page 4). The minimum dropout voltage is 1V (which give a minimum voltage of 6v ) when the current very low (around 0) and the junction temperature is 20C (figure 1, page 9). That been said, in many application you will draw more current which will raise the drop-out voltage.
The actual maximum voltage is also determined by the current since an increase in current will result in a increase in power dissipated by the junction which in turn increase the junction temperature . If the junction temperature goes beyond 120C, you will need the decrease the input voltage to decrease the temperature. The maximum power dissipated by the junction is given by the formula Pd = (125 -Ta)/61.6, where Pd is the maximum allowable power dissipation and Ta is the ambient temperature (in Celsius) [base on note 1 of Recommended Operating Conditions, page 4].

Personally, I prefer the 7-12V range since it take in account more use cases.